Solve 87^3-57^3/87^2+8*7*5*7+57^2

$$\frac{ 8 { 7 }^{ 3 } -5 { 7 }^{ 3 } }{ 8 { 7 }^{ 2 } +8 \cdot 7 \times 5 \cdot 7+5 { 7 }^{ 2 } }$$

Evaluate

$$\frac{21}{53}\approx 0.396226415$$

Solution Steps

Calculate 7 to the power of 3 and get 343.

$$\frac{8\times 343-5\times 7^{3}}{8\times 7^{2}+8\times 7\times 5\times 7+5\times 7^{2}}$$

Multiply 8 and 343 to get 2744.

$$\frac{2744-5\times 7^{3}}{8\times 7^{2}+8\times 7\times 5\times 7+5\times 7^{2}}$$

Calculate 7 to the power of 3 and get 343.

$$\frac{2744-5\times 343}{8\times 7^{2}+8\times 7\times 5\times 7+5\times 7^{2}}$$

Multiply 5 and 343 to get 1715.

$$\frac{2744-1715}{8\times 7^{2}+8\times 7\times 5\times 7+5\times 7^{2}}$$

Subtract 1715 from 2744 to get 1029.

$$\frac{1029}{8\times 7^{2}+8\times 7\times 5\times 7+5\times 7^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{1029}{8\times 49+8\times 7\times 5\times 7+5\times 7^{2}}$$

Multiply 8 and 49 to get 392.

$$\frac{1029}{392+8\times 7\times 5\times 7+5\times 7^{2}}$$

Multiply 8 and 7 to get 56.

$$\frac{1029}{392+56\times 5\times 7+5\times 7^{2}}$$

Multiply 56 and 5 to get 280.

$$\frac{1029}{392+280\times 7+5\times 7^{2}}$$

Multiply 280 and 7 to get 1960.

$$\frac{1029}{392+1960+5\times 7^{2}}$$

Add 392 and 1960 to get 2352.

$$\frac{1029}{2352+5\times 7^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{1029}{2352+5\times 49}$$

Multiply 5 and 49 to get 245.

$$\frac{1029}{2352+245}$$

Add 2352 and 245 to get 2597.

$$\frac{1029}{2597}$$

Reduce the fraction \frac{1029}{2597} to lowest terms by extracting and canceling out 49.

$$\frac{21}{53}$$

Factor

$$\frac{3 \cdot 7}{53} = 0.39622641509433965$$