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\frac{8}{9}x=\frac{1}{6}-3
Subtract 3 from both sides.
\frac{8}{9}x=\frac{1}{6}-\frac{18}{6}
Convert 3 to fraction \frac{18}{6}.
\frac{8}{9}x=\frac{1-18}{6}
Since \frac{1}{6} and \frac{18}{6} have the same denominator, subtract them by subtracting their numerators.
\frac{8}{9}x=-\frac{17}{6}
Subtract 18 from 1 to get -17.
x=-\frac{17}{6}\times \frac{9}{8}
Multiply both sides by \frac{9}{8}, the reciprocal of \frac{8}{9}.
x=\frac{-17\times 9}{6\times 8}
Multiply -\frac{17}{6} times \frac{9}{8} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-153}{48}
Do the multiplications in the fraction \frac{-17\times 9}{6\times 8}.
x=-\frac{51}{16}
Reduce the fraction \frac{-153}{48} to lowest terms by extracting and canceling out 3.