Solve 8/9+lceil4/9rceil

$$\frac{ 8 }{ 9 } + \lceil \frac{ 4 }{ 9 } \rceil$$

Evaluate

$$\frac{17}{9}\approx 1.888888889$$

Solution Steps

Dividing 4 by 9 gives 0 and remainder 4. Rewrite \frac{4}{9} as 0+\frac{4}{9}.

$$\frac{8}{9}+\lceil 0+\frac{4}{9}\rceil$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 0+\frac{4}{9} is 1.

$$\frac{8}{9}+1$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{8}{9}+\frac{9}{9}$$

Since \frac{8}{9} and \frac{9}{9} have the same denominator, add them by adding their numerators.

$$\frac{8+9}{9}$$

Add 8 and 9 to get 17.

$$\frac{17}{9}$$

Factor

$$\frac{17}{3 ^ {2}} = 1\frac{8}{9} = 1.8888888888888888$$