Solve 8/3-19/2+16/9

$$\frac{ 8 }{ 3 } - \frac{ 19 }{ 2 } + \frac{ 16 }{ 9 }$$

Evaluate

$$-\frac{91}{18}\approx -5.055555556$$

Solution Steps

Least common multiple of 3 and 2 is 6. Convert \frac{8}{3} and \frac{19}{2} to fractions with denominator 6.

$$\frac{16}{6}-\frac{57}{6}+\frac{16}{9}$$

Since \frac{16}{6} and \frac{57}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-57}{6}+\frac{16}{9}$$

Subtract 57 from 16 to get -41.

$$-\frac{41}{6}+\frac{16}{9}$$

Least common multiple of 6 and 9 is 18. Convert -\frac{41}{6} and \frac{16}{9} to fractions with denominator 18.

$$-\frac{123}{18}+\frac{32}{18}$$

Since -\frac{123}{18} and \frac{32}{18} have the same denominator, add them by adding their numerators.

$$\frac{-123+32}{18}$$

Add -123 and 32 to get -91.

$$-\frac{91}{18}$$

Factor

$$-\frac{91}{18} = -5\frac{1}{18} = -5.055555555555555$$