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\frac{8}{2-\sqrt{2}}
Calculate the square root of 4 and get 2.
\frac{8\left(2+\sqrt{2}\right)}{\left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right)}
Rationalize the denominator of \frac{8}{2-\sqrt{2}} by multiplying numerator and denominator by 2+\sqrt{2}.
\frac{8\left(2+\sqrt{2}\right)}{2^{2}-\left(\sqrt{2}\right)^{2}}
Consider \left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{8\left(2+\sqrt{2}\right)}{4-2}
Square 2. Square \sqrt{2}.
\frac{8\left(2+\sqrt{2}\right)}{2}
Subtract 2 from 4 to get 2.
4\left(2+\sqrt{2}\right)
Divide 8\left(2+\sqrt{2}\right) by 2 to get 4\left(2+\sqrt{2}\right).
8+4\sqrt{2}
Use the distributive property to multiply 4 by 2+\sqrt{2}.