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77=7xx+7x\times 7x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 7x.
77=7x^{2}+7x\times 7x
Multiply x and x to get x^{2}.
77=7x^{2}+7x^{2}\times 7
Multiply x and x to get x^{2}.
77=7x^{2}+49x^{2}
Multiply 7 and 7 to get 49.
77=56x^{2}
Combine 7x^{2} and 49x^{2} to get 56x^{2}.
56x^{2}=77
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{77}{56}
Divide both sides by 56.
x^{2}=\frac{11}{8}
Reduce the fraction \frac{77}{56} to lowest terms by extracting and canceling out 7.
x=\frac{\sqrt{22}}{4} x=-\frac{\sqrt{22}}{4}
Take the square root of both sides of the equation.
77=7xx+7x\times 7x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 7x.
77=7x^{2}+7x\times 7x
Multiply x and x to get x^{2}.
77=7x^{2}+7x^{2}\times 7
Multiply x and x to get x^{2}.
77=7x^{2}+49x^{2}
Multiply 7 and 7 to get 49.
77=56x^{2}
Combine 7x^{2} and 49x^{2} to get 56x^{2}.
56x^{2}=77
Swap sides so that all variable terms are on the left hand side.
56x^{2}-77=0
Subtract 77 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times 56\left(-77\right)}}{2\times 56}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 56 for a, 0 for b, and -77 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 56\left(-77\right)}}{2\times 56}
Square 0.
x=\frac{0±\sqrt{-224\left(-77\right)}}{2\times 56}
Multiply -4 times 56.
x=\frac{0±\sqrt{17248}}{2\times 56}
Multiply -224 times -77.
x=\frac{0±28\sqrt{22}}{2\times 56}
Take the square root of 17248.
x=\frac{0±28\sqrt{22}}{112}
Multiply 2 times 56.
x=\frac{\sqrt{22}}{4}
Now solve the equation x=\frac{0±28\sqrt{22}}{112} when ± is plus.
x=-\frac{\sqrt{22}}{4}
Now solve the equation x=\frac{0±28\sqrt{22}}{112} when ± is minus.
x=\frac{\sqrt{22}}{4} x=-\frac{\sqrt{22}}{4}
The equation is now solved.