Solve 7-3*(-8)+(-3^2/-2^3

$$\frac{ 7-3 \times (-8)+( { -3 }^{ 2 } }{ { -2 }^{ 3 } }$$

Evaluate

$$\frac{239}{8}=29.875$$

Solution Steps

Multiply 3 and -8 to get -24.

$$7-\left(-24\right)+\frac{\left(-3\right)^{2}}{\left(-2\right)^{3}}$$

The opposite of -24 is 24.

$$7+24+\frac{\left(-3\right)^{2}}{\left(-2\right)^{3}}$$

Add 7 and 24 to get 31.

$$31+\frac{\left(-3\right)^{2}}{\left(-2\right)^{3}}$$

Calculate -3 to the power of 2 and get 9.

$$31+\frac{9}{\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$31+\frac{9}{-8}$$

Fraction \frac{9}{-8} can be rewritten as -\frac{9}{8} by extracting the negative sign.

$$31-\frac{9}{8}$$

Convert 31 to fraction \frac{248}{8}.

$$\frac{248}{8}-\frac{9}{8}$$

Since \frac{248}{8} and \frac{9}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{248-9}{8}$$

Subtract 9 from 248 to get 239.

$$\frac{239}{8}$$

Factor

$$\frac{239}{2 ^ {3}} = 29\frac{7}{8} = 29.875$$