Solve for x_3
x_{3}\geq 17
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7+9+x_{3}\geq 11\times 3
Multiply both sides by 3. Since 3 is positive, the inequality direction remains the same.
16+x_{3}\geq 11\times 3
Add 7 and 9 to get 16.
16+x_{3}\geq 33
Multiply 11 and 3 to get 33.
x_{3}\geq 33-16
Subtract 16 from both sides.
x_{3}\geq 17
Subtract 16 from 33 to get 17.
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