Solve 7+9+x*3/3geq11

$$\frac{ 7+9+x \times 3 }{ 3 } \geq 11$$

Solve for x

$$x\geq \frac{17}{3}$$

Solution Steps

Multiply both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$7+9+x\times 3\geq 11\times 3$$

Add 7 and 9 to get 16.

$$16+x\times 3\geq 11\times 3$$

Multiply 11 and 3 to get 33.

$$16+x\times 3\geq 33$$

Subtract 16 from both sides.

$$x\times 3\geq 33-16$$

Subtract 16 from 33 to get 17.

$$x\times 3\geq 17$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x\geq \frac{17}{3}$$