Solve 7left(x+4right)/3=7x+42/2

$$\frac{ 7 \left( x+4 \right) }{ 3 } = \frac{ 7x+42 }{ 2 }$$

Solve for x

$$x=-10$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 6, the least common multiple of 3,2.

$$2\times 7\left(x+4\right)=3\left(7x+42\right)$$

Multiply 2 and 7 to get 14.

$$14\left(x+4\right)=3\left(7x+42\right)$$

Use the distributive property to multiply 14 by x+4.

$$14x+56=3\left(7x+42\right)$$

Use the distributive property to multiply 3 by 7x+42.

$$14x+56=21x+126$$

Subtract 21x from both sides.

$$14x+56-21x=126$$

Combine 14x and -21x to get -7x.

$$-7x+56=126$$

Subtract 56 from both sides.

$$-7x=126-56$$

Subtract 56 from 126 to get 70.

$$-7x=70$$

Divide both sides by -7.

$$x=\frac{70}{-7}$$

Divide 70 by -7 to get -10.

$$x=-10$$