Solve 7/8+4+8/

$$\frac{ 7 }{ 8 } +4+ \frac{ 8 }{ }$$

Evaluate

$$\frac{103}{8}=12.875$$

Solution Steps

Convert 4 to fraction \frac{32}{8}.

$$\frac{7}{8}+\frac{32}{8}+\frac{8}{1}$$

Since \frac{7}{8} and \frac{32}{8} have the same denominator, add them by adding their numerators.

$$\frac{7+32}{8}+\frac{8}{1}$$

Add 7 and 32 to get 39.

$$\frac{39}{8}+\frac{8}{1}$$

Anything divided by one gives itself.

$$\frac{39}{8}+8$$

Convert 8 to fraction \frac{64}{8}.

$$\frac{39}{8}+\frac{64}{8}$$

Since \frac{39}{8} and \frac{64}{8} have the same denominator, add them by adding their numerators.

$$\frac{39+64}{8}$$

Add 39 and 64 to get 103.

$$\frac{103}{8}$$

Factor

$$\frac{103}{2 ^ {3}} = 12\frac{7}{8} = 12.875$$