Solve 7/8+7/8+1/4+1/16

$$\frac{ 7 }{ 8 } + \frac{ 7 }{ 8 } + \frac{ 1 }{ 4 } + \frac{ 1 }{ 16 }$$

Evaluate

$$\frac{33}{16}=2.0625$$

Solution Steps

Since \frac{7}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.

$$\frac{7+7}{8}+\frac{1}{4}+\frac{1}{16}$$

Add 7 and 7 to get 14.

$$\frac{14}{8}+\frac{1}{4}+\frac{1}{16}$$

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$\frac{7}{4}+\frac{1}{4}+\frac{1}{16}$$

Since \frac{7}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{7+1}{4}+\frac{1}{16}$$

Add 7 and 1 to get 8.

$$\frac{8}{4}+\frac{1}{16}$$

Divide 8 by 4 to get 2.

$$2+\frac{1}{16}$$

Convert 2 to fraction \frac{32}{16}.

$$\frac{32}{16}+\frac{1}{16}$$

Since \frac{32}{16} and \frac{1}{16} have the same denominator, add them by adding their numerators.

$$\frac{32+1}{16}$$

Add 32 and 1 to get 33.

$$\frac{33}{16}$$

Factor

$$\frac{3 \cdot 11}{2 ^ {4}} = 2\frac{1}{16} = 2.0625$$