Solve 7/8+1/4*(3/2-5/8)

$$\frac{ 7 }{ 8 } + \frac{ 1 }{ 4 } \times ( \frac{ 3 }{ 2 } - \frac{ 5 }{ 8 } )$$

Evaluate

$$\frac{35}{32}=1.09375$$

Solution Steps

Least common multiple of 2 and 8 is 8. Convert \frac{3}{2} and \frac{5}{8} to fractions with denominator 8.

$$\frac{7}{8}+\frac{1}{4}\left(\frac{12}{8}-\frac{5}{8}\right)$$

Since \frac{12}{8} and \frac{5}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{8}+\frac{1}{4}\times \frac{12-5}{8}$$

Subtract 5 from 12 to get 7.

$$\frac{7}{8}+\frac{1}{4}\times \frac{7}{8}$$

Multiply \frac{1}{4} times \frac{7}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{8}+\frac{1\times 7}{4\times 8}$$

Do the multiplications in the fraction \frac{1\times 7}{4\times 8}.

$$\frac{7}{8}+\frac{7}{32}$$

Least common multiple of 8 and 32 is 32. Convert \frac{7}{8} and \frac{7}{32} to fractions with denominator 32.

$$\frac{28}{32}+\frac{7}{32}$$

Since \frac{28}{32} and \frac{7}{32} have the same denominator, add them by adding their numerators.

$$\frac{28+7}{32}$$

Add 28 and 7 to get 35.

$$\frac{35}{32}$$

Factor

$$\frac{5 \cdot 7}{2 ^ {5}} = 1\frac{3}{32} = 1.09375$$