Solve 7/4x-7/4=-6x-5/3

$$\frac{ 7 }{ 4 } x- \frac{ 7 }{ 4 } =-6x- \frac{ 5 }{ 3 }$$

Solve for x

$$x=\frac{1}{93}\approx 0.010752688$$

Steps for Solving Linear Equation

Add 6x to both sides.

$$\frac{7}{4}x-\frac{7}{4}+6x=-\frac{5}{3}$$

Combine \frac{7}{4}x and 6x to get \frac{31}{4}x.

$$\frac{31}{4}x-\frac{7}{4}=-\frac{5}{3}$$

Add \frac{7}{4} to both sides.

$$\frac{31}{4}x=-\frac{5}{3}+\frac{7}{4}$$

Least common multiple of 3 and 4 is 12. Convert -\frac{5}{3} and \frac{7}{4} to fractions with denominator 12.

$$\frac{31}{4}x=-\frac{20}{12}+\frac{21}{12}$$

Since -\frac{20}{12} and \frac{21}{12} have the same denominator, add them by adding their numerators.

$$\frac{31}{4}x=\frac{-20+21}{12}$$

Add -20 and 21 to get 1.

$$\frac{31}{4}x=\frac{1}{12}$$

Multiply both sides by \frac{4}{31}, the reciprocal of \frac{31}{4}.

$$x=\frac{1}{12}\times \frac{4}{31}$$

Multiply \frac{1}{12} times \frac{4}{31} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{1\times 4}{12\times 31}$$

Do the multiplications in the fraction \frac{1\times 4}{12\times 31}.

$$x=\frac{4}{372}$$

Reduce the fraction \frac{4}{372} to lowest terms by extracting and canceling out 4.

$$x=\frac{1}{93}$$