Solve 7/3-2/3*(1-2/3)

$$\frac{ 7 }{ 3 } - \frac{ 2 }{ 3 } \times (1- \frac{ 2 }{ 3 } )$$

Evaluate

$$\frac{19}{9}\approx 2.111111111$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{7}{3}-\frac{2}{3}\left(\frac{3}{3}-\frac{2}{3}\right)$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7}{3}-\frac{2}{3}\times \frac{3-2}{3}$$

Subtract 2 from 3 to get 1.

$$\frac{7}{3}-\frac{2}{3}\times \frac{1}{3}$$

Multiply \frac{2}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{3}-\frac{2\times 1}{3\times 3}$$

Do the multiplications in the fraction \frac{2\times 1}{3\times 3}.

$$\frac{7}{3}-\frac{2}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{7}{3} and \frac{2}{9} to fractions with denominator 9.

$$\frac{21}{9}-\frac{2}{9}$$

Since \frac{21}{9} and \frac{2}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-2}{9}$$

Subtract 2 from 21 to get 19.

$$\frac{19}{9}$$

Factor

$$\frac{19}{3 ^ {2}} = 2\frac{1}{9} = 2.111111111111111$$