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x^{2}=\frac{3}{7}\times \frac{3}{7}
Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.
x^{2}=\frac{9}{49}
Multiply \frac{3}{7} and \frac{3}{7} to get \frac{9}{49}.
x^{2}-\frac{9}{49}=0
Subtract \frac{9}{49} from both sides.
49x^{2}-9=0
Multiply both sides by 49.
\left(7x-3\right)\left(7x+3\right)=0
Consider 49x^{2}-9. Rewrite 49x^{2}-9 as \left(7x\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{3}{7} x=-\frac{3}{7}
To find equation solutions, solve 7x-3=0 and 7x+3=0.
x^{2}=\frac{3}{7}\times \frac{3}{7}
Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.
x^{2}=\frac{9}{49}
Multiply \frac{3}{7} and \frac{3}{7} to get \frac{9}{49}.
x=\frac{3}{7} x=-\frac{3}{7}
Take the square root of both sides of the equation.
x^{2}=\frac{3}{7}\times \frac{3}{7}
Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.
x^{2}=\frac{9}{49}
Multiply \frac{3}{7} and \frac{3}{7} to get \frac{9}{49}.
x^{2}-\frac{9}{49}=0
Subtract \frac{9}{49} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{9}{49}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{9}{49} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{9}{49}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{36}{49}}}{2}
Multiply -4 times -\frac{9}{49}.
x=\frac{0±\frac{6}{7}}{2}
Take the square root of \frac{36}{49}.
x=\frac{3}{7}
Now solve the equation x=\frac{0±\frac{6}{7}}{2} when ± is plus.
x=-\frac{3}{7}
Now solve the equation x=\frac{0±\frac{6}{7}}{2} when ± is minus.
x=\frac{3}{7} x=-\frac{3}{7}
The equation is now solved.