Solve 64*7^3*7^11/2^7*7^6*{7^7}

$$\frac{ 64 \times { 7 }^{ 3 } \times { 7 }^{ 11 } }{ { 2 }^{ 7 } \times { 7 }^{ 6 } \times { 7 }^{ 7 } }$$

Evaluate

$$\frac{7}{2}=3.5$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 11 to get 14.

$$\frac{64\times 7^{14}}{2^{7}\times 7^{6}\times 7^{7}}$$

To multiply powers of the same base, add their exponents. Add 6 and 7 to get 13.

$$\frac{64\times 7^{14}}{2^{7}\times 7^{13}}$$

Cancel out 7^{13} in both numerator and denominator.

$$\frac{7\times 64}{2^{7}}$$

Multiply 7 and 64 to get 448.

$$\frac{448}{2^{7}}$$

Calculate 2 to the power of 7 and get 128.

$$\frac{448}{128}$$

Reduce the fraction \frac{448}{128} to lowest terms by extracting and canceling out 64.

$$\frac{7}{2}$$

Factor

$$\frac{7}{2} = 3\frac{1}{2} = 3.5$$