Solve 6-NC/6=NM/4

$$\frac{ 6-NC }{ 6 } = \frac{ NM }{ 4 }$$

Solve for C

$$C=-\frac{3M}{2}+\frac{6}{N}$$

$$N\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 6,4.

$$2\left(6-NC\right)=3NM$$

Use the distributive property to multiply 2 by 6-NC.

$$12-2NC=3NM$$

Subtract 12 from both sides.

$$-2NC=3NM-12$$

The equation is in standard form.

$$\left(-2N\right)C=3MN-12$$

Divide both sides by -2N.

$$\frac{\left(-2N\right)C}{-2N}=\frac{3MN-12}{-2N}$$

Dividing by -2N undoes the multiplication by -2N.

$$C=\frac{3MN-12}{-2N}$$

Divide 3NM-12 by -2N.

$$C=-\frac{3M}{2}+\frac{6}{N}$$

Solve for M

$$M=-\frac{2C}{3}+\frac{4}{N}$$

$$N\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 6,4.

$$2\left(6-NC\right)=3NM$$

Use the distributive property to multiply 2 by 6-NC.

$$12-2NC=3NM$$

Swap sides so that all variable terms are on the left hand side.

$$3NM=12-2NC$$

The equation is in standard form.

$$3NM=12-2CN$$

Divide both sides by 3N.

$$\frac{3NM}{3N}=\frac{12-2CN}{3N}$$

Dividing by 3N undoes the multiplication by 3N.

$$M=\frac{12-2CN}{3N}$$

Divide 12-2NC by 3N.

$$M=-\frac{2C}{3}+\frac{4}{N}$$