Solve 6(2^2-1)+50/2+4-2

$$\frac{ 6( { 2 }^{ 2 } -1)+50 }{ 2+4-2 }$$

Evaluate

$$17$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{6\left(4-1\right)+50}{2+4-2}$$

Subtract 1 from 4 to get 3.

$$\frac{6\times 3+50}{2+4-2}$$

Multiply 6 and 3 to get 18.

$$\frac{18+50}{2+4-2}$$

Add 18 and 50 to get 68.

$$\frac{68}{2+4-2}$$

Add 2 and 4 to get 6.

$$\frac{68}{6-2}$$

Subtract 2 from 6 to get 4.

$$\frac{68}{4}$$

Divide 68 by 4 to get 17.

$$17$$

Factor

$$17$$