Solve for x
x=3
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\left(x+43\right)\left(6+x\right)=\left(x+15\right)\left(20+x\right)
Variable x cannot be equal to any of the values -43,-15 since division by zero is not defined. Multiply both sides of the equation by \left(x+15\right)\left(x+43\right), the least common multiple of 15+x,43+x.
49x+x^{2}+258=\left(x+15\right)\left(20+x\right)
Use the distributive property to multiply x+43 by 6+x and combine like terms.
49x+x^{2}+258=35x+x^{2}+300
Use the distributive property to multiply x+15 by 20+x and combine like terms.
49x+x^{2}+258-35x=x^{2}+300
Subtract 35x from both sides.
14x+x^{2}+258=x^{2}+300
Combine 49x and -35x to get 14x.
14x+x^{2}+258-x^{2}=300
Subtract x^{2} from both sides.
14x+258=300
Combine x^{2} and -x^{2} to get 0.
14x=300-258
Subtract 258 from both sides.
14x=42
Subtract 258 from 300 to get 42.
x=\frac{42}{14}
Divide both sides by 14.
x=3
Divide 42 by 14 to get 3.
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