Solve 6*91.5-27*18.9/6139^2-27^2

$$\frac{ 6 \cdot 91.5-27 \cdot 18.9 }{ 6 { 139 }^{ 2 } - { 27 }^{ 2 } }$$

Evaluate

$$\frac{3}{8930}\approx 0.000335946$$

Solution Steps

Multiply 6 and 91.5 to get 549.

$$\frac{549-27\times 18.9}{6\times 139^{2}-27^{2}}$$

Multiply 27 and 18.9 to get 510.3.

$$\frac{549-510.3}{6\times 139^{2}-27^{2}}$$

Subtract 510.3 from 549 to get 38.7.

$$\frac{38.7}{6\times 139^{2}-27^{2}}$$

Calculate 139 to the power of 2 and get 19321.

$$\frac{38.7}{6\times 19321-27^{2}}$$

Multiply 6 and 19321 to get 115926.

$$\frac{38.7}{115926-27^{2}}$$

Calculate 27 to the power of 2 and get 729.

$$\frac{38.7}{115926-729}$$

Subtract 729 from 115926 to get 115197.

$$\frac{38.7}{115197}$$

Expand \frac{38.7}{115197} by multiplying both numerator and the denominator by 10.

$$\frac{387}{1151970}$$

Reduce the fraction \frac{387}{1151970} to lowest terms by extracting and canceling out 129.

$$\frac{3}{8930}$$

Factor

$$\frac{3}{2 \cdot 5 \cdot 19 \cdot 47} = 0.00033594624860022396$$