Solve 6*2/6+2+2*3/2+3

$$\frac{ 6 \cdot 2 }{ 6+2 } + \frac{ 2 \times 3 }{ 2+3 }$$

Evaluate

$$\frac{27}{10}=2.7$$

Solution Steps

Multiply 6 and 2 to get 12.

$$\frac{12}{6+2}+\frac{2\times 3}{2+3}$$

Add 6 and 2 to get 8.

$$\frac{12}{8}+\frac{2\times 3}{2+3}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}+\frac{2\times 3}{2+3}$$

Multiply 2 and 3 to get 6.

$$\frac{3}{2}+\frac{6}{2+3}$$

Add 2 and 3 to get 5.

$$\frac{3}{2}+\frac{6}{5}$$

Least common multiple of 2 and 5 is 10. Convert \frac{3}{2} and \frac{6}{5} to fractions with denominator 10.

$$\frac{15}{10}+\frac{12}{10}$$

Since \frac{15}{10} and \frac{12}{10} have the same denominator, add them by adding their numerators.

$$\frac{15+12}{10}$$

Add 15 and 12 to get 27.

$$\frac{27}{10}$$

Factor

$$\frac{3 ^ {3}}{2 \cdot 5} = 2\frac{7}{10} = 2.7$$