Solve 6/x+4-2/x

$$\frac{ 6 }{ x+4 } - \frac{ 2 }{ x }$$

Evaluate

$$\frac{4\left(x-2\right)}{x\left(x+4\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+4 and x is x\left(x+4\right). Multiply \frac{6}{x+4} times \frac{x}{x}. Multiply \frac{2}{x} times \frac{x+4}{x+4}.

$$\frac{6x}{x\left(x+4\right)}-\frac{2\left(x+4\right)}{x\left(x+4\right)}$$

Since \frac{6x}{x\left(x+4\right)} and \frac{2\left(x+4\right)}{x\left(x+4\right)} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6x-2\left(x+4\right)}{x\left(x+4\right)}$$

Do the multiplications in 6x-2\left(x+4\right).

$$\frac{6x-2x-8}{x\left(x+4\right)}$$

Combine like terms in 6x-2x-8.

$$\frac{4x-8}{x\left(x+4\right)}$$

Expand x\left(x+4\right).

$$\frac{4x-8}{x^{2}+4x}$$

Factor

$$\frac{4\left(x-2\right)}{x\left(x+4\right)}$$