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\frac{3\left(5x-1\right)}{6}+\frac{2\left(x+1\right)}{6}=x
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2 and 3 is 6. Multiply \frac{5x-1}{2} times \frac{3}{3}. Multiply \frac{x+1}{3} times \frac{2}{2}.
\frac{3\left(5x-1\right)+2\left(x+1\right)}{6}=x
Since \frac{3\left(5x-1\right)}{6} and \frac{2\left(x+1\right)}{6} have the same denominator, add them by adding their numerators.
\frac{15x-3+2x+2}{6}=x
Do the multiplications in 3\left(5x-1\right)+2\left(x+1\right).
\frac{17x-1}{6}=x
Combine like terms in 15x-3+2x+2.
\frac{17}{6}x-\frac{1}{6}=x
Divide each term of 17x-1 by 6 to get \frac{17}{6}x-\frac{1}{6}.
\frac{17}{6}x-\frac{1}{6}-x=0
Subtract x from both sides.
\frac{11}{6}x-\frac{1}{6}=0
Combine \frac{17}{6}x and -x to get \frac{11}{6}x.
\frac{11}{6}x=\frac{1}{6}
Add \frac{1}{6} to both sides. Anything plus zero gives itself.
x=\frac{1}{6}\times \frac{6}{11}
Multiply both sides by \frac{6}{11}, the reciprocal of \frac{11}{6}.
x=\frac{1\times 6}{6\times 11}
Multiply \frac{1}{6} times \frac{6}{11} by multiplying numerator times numerator and denominator times denominator.
x=\frac{1}{11}
Cancel out 6 in both numerator and denominator.