Solve 5t-3k+3/8=x

$$\frac{ 5t-3k+3 }{ 8 } =x$$

Solve for k

$$k=\frac{5t}{3}-\frac{8x}{3}+1$$

Steps for Solving Linear Equation

Divide each term of 5t-3k+3 by 8 to get \frac{5}{8}t-\frac{3}{8}k+\frac{3}{8}.

$$\frac{5}{8}t-\frac{3}{8}k+\frac{3}{8}=x$$

Subtract \frac{5}{8}t from both sides.

$$-\frac{3}{8}k+\frac{3}{8}=x-\frac{5}{8}t$$

Subtract \frac{3}{8} from both sides.

$$-\frac{3}{8}k=x-\frac{5}{8}t-\frac{3}{8}$$

The equation is in standard form.

$$-\frac{3}{8}k=-\frac{5t}{8}+x-\frac{3}{8}$$

Divide both sides of the equation by -\frac{3}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-\frac{3}{8}k}{-\frac{3}{8}}=\frac{-\frac{5t}{8}+x-\frac{3}{8}}{-\frac{3}{8}}$$

Dividing by -\frac{3}{8} undoes the multiplication by -\frac{3}{8}.

$$k=\frac{-\frac{5t}{8}+x-\frac{3}{8}}{-\frac{3}{8}}$$

Divide x-\frac{5t}{8}-\frac{3}{8} by -\frac{3}{8} by multiplying x-\frac{5t}{8}-\frac{3}{8} by the reciprocal of -\frac{3}{8}.

$$k=\frac{5t}{3}-\frac{8x}{3}+1$$

Solve for t

$$t=\frac{8x+3k-3}{5}$$

Steps for Solving Linear Equation

Divide each term of 5t-3k+3 by 8 to get \frac{5}{8}t-\frac{3}{8}k+\frac{3}{8}.

$$\frac{5}{8}t-\frac{3}{8}k+\frac{3}{8}=x$$

Add \frac{3}{8}k to both sides.

$$\frac{5}{8}t+\frac{3}{8}=x+\frac{3}{8}k$$

Subtract \frac{3}{8} from both sides.

$$\frac{5}{8}t=x+\frac{3}{8}k-\frac{3}{8}$$

The equation is in standard form.

$$\frac{5}{8}t=\frac{3k}{8}+x-\frac{3}{8}$$

Divide both sides of the equation by \frac{5}{8}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{8}t}{\frac{5}{8}}=\frac{\frac{3k}{8}+x-\frac{3}{8}}{\frac{5}{8}}$$

Dividing by \frac{5}{8} undoes the multiplication by \frac{5}{8}.

$$t=\frac{\frac{3k}{8}+x-\frac{3}{8}}{\frac{5}{8}}$$

Divide x+\frac{3k}{8}-\frac{3}{8} by \frac{5}{8} by multiplying x+\frac{3k}{8}-\frac{3}{8} by the reciprocal of \frac{5}{8}.

$$t=\frac{8x+3k-3}{5}$$