Solve 5000*10^3*1.8/3300^2*100

$$\frac{ 5000 \times { 10 }^{ 3 } \times 1.8 }{ { 3300 }^{ 2 } } \times 100$$

Evaluate

$$\frac{10000}{121}\approx 82.644628099$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$\frac{5000\times 1000\times 1.8}{3300^{2}}\times 100$$

Multiply 5000 and 1000 to get 5000000.

$$\frac{5000000\times 1.8}{3300^{2}}\times 100$$

Multiply 5000000 and 1.8 to get 9000000.

$$\frac{9000000}{3300^{2}}\times 100$$

Calculate 3300 to the power of 2 and get 10890000.

$$\frac{9000000}{10890000}\times 100$$

Reduce the fraction \frac{9000000}{10890000} to lowest terms by extracting and canceling out 90000.

$$\frac{100}{121}\times 100$$

Express \frac{100}{121}\times 100 as a single fraction.

$$\frac{100\times 100}{121}$$

Multiply 100 and 100 to get 10000.

$$\frac{10000}{121}$$

Factor

$$\frac{2 ^ {4} \cdot 5 ^ {4}}{11 ^ {2}} = 82\frac{78}{121} = 82.64462809917356$$