Solve 50/1.01+35/105^2=

$$\frac{ 50 }{ 1.01 } + \frac{ 35 }{ { 105 }^{ 2 } } =$$

Evaluate

$$\frac{1575101}{31815}\approx 49.508125098$$

Solution Steps

Expand \frac{50}{1.01} by multiplying both numerator and the denominator by 100.

$$\frac{5000}{101}+\frac{35}{105^{2}}$$

Calculate 105 to the power of 2 and get 11025.

$$\frac{5000}{101}+\frac{35}{11025}$$

Reduce the fraction \frac{35}{11025} to lowest terms by extracting and canceling out 35.

$$\frac{5000}{101}+\frac{1}{315}$$

Least common multiple of 101 and 315 is 31815. Convert \frac{5000}{101} and \frac{1}{315} to fractions with denominator 31815.

$$\frac{1575000}{31815}+\frac{101}{31815}$$

Since \frac{1575000}{31815} and \frac{101}{31815} have the same denominator, add them by adding their numerators.

$$\frac{1575000+101}{31815}$$

Add 1575000 and 101 to get 1575101.

$$\frac{1575101}{31815}$$

Factor

$$\frac{11 \cdot 17 \cdot 8423}{5 \cdot 7 \cdot 101 \cdot 3 ^ {2}} = 49\frac{16166}{31815} = 49.508125098224106$$