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Solve for x
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5=-5xz
Multiply both sides of the equation by z.
-5xz=5
Swap sides so that all variable terms are on the left hand side.
\left(-5z\right)x=5
The equation is in standard form.
\frac{\left(-5z\right)x}{-5z}=\frac{5}{-5z}
Divide both sides by -5z.
x=\frac{5}{-5z}
Dividing by -5z undoes the multiplication by -5z.
x=-\frac{1}{z}
Divide 5 by -5z.
5=-5xz
Variable z cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by z.
-5xz=5
Swap sides so that all variable terms are on the left hand side.
\left(-5x\right)z=5
The equation is in standard form.
\frac{\left(-5x\right)z}{-5x}=\frac{5}{-5x}
Divide both sides by -5x.
z=\frac{5}{-5x}
Dividing by -5x undoes the multiplication by -5x.
z=-\frac{1}{x}
Divide 5 by -5x.
z=-\frac{1}{x}\text{, }z\neq 0
Variable z cannot be equal to 0.