Solve 5/8lfloor5.2rfloor4^2=

$$\frac{ 5 }{ 8 } \lfloor 5.2 \rfloor { 4 }^{ 2 } =$$

Evaluate

$$50$$

Solution Steps

The floor of a real number a is the largest integer number less than or equal to a. The floor of 5.2 is 5.

$$\frac{5}{8}\times 5\times 4^{2}$$

Express \frac{5}{8}\times 5 as a single fraction.

$$\frac{5\times 5}{8}\times 4^{2}$$

Multiply 5 and 5 to get 25.

$$\frac{25}{8}\times 4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{25}{8}\times 16$$

Express \frac{25}{8}\times 16 as a single fraction.

$$\frac{25\times 16}{8}$$

Multiply 25 and 16 to get 400.

$$\frac{400}{8}$$

Divide 400 by 8 to get 50.

$$50$$

Factor

$$2\times 5^{2}$$