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\frac{5\times 3}{7\left(1\times 3+2\right)}
Divide \frac{5}{7} by \frac{1\times 3+2}{3} by multiplying \frac{5}{7} by the reciprocal of \frac{1\times 3+2}{3}.
\frac{15}{7\left(1\times 3+2\right)}
Multiply 5 and 3 to get 15.
\frac{15}{7\left(3+2\right)}
Multiply 1 and 3 to get 3.
\frac{15}{7\times 5}
Add 3 and 2 to get 5.
\frac{15}{35}
Multiply 7 and 5 to get 35.
\frac{3}{7}
Reduce the fraction \frac{15}{35} to lowest terms by extracting and canceling out 5.