Solve 5/612-60/8-3/8-1*12=7

$$\frac{ 5 }{ 6 } 12- \frac{ 60 }{ 8 } - \frac{ 3 }{ 8 } -1 \cdot 12 = 7$$

Verify

Solution Steps

Express \frac{5}{6}\times 12 as a single fraction.

$$\frac{5\times 12}{6}-\frac{60}{8}-\frac{3}{8}-1\times 12=7$$

Multiply 5 and 12 to get 60.

$$\frac{60}{6}-\frac{60}{8}-\frac{3}{8}-1\times 12=7$$

Divide 60 by 6 to get 10.

$$10-\frac{60}{8}-\frac{3}{8}-1\times 12=7$$

Reduce the fraction \frac{60}{8} to lowest terms by extracting and canceling out 4.

$$10-\frac{15}{2}-\frac{3}{8}-1\times 12=7$$

Convert 10 to fraction \frac{20}{2}.

$$\frac{20}{2}-\frac{15}{2}-\frac{3}{8}-1\times 12=7$$

Since \frac{20}{2} and \frac{15}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-15}{2}-\frac{3}{8}-1\times 12=7$$

Subtract 15 from 20 to get 5.

$$\frac{5}{2}-\frac{3}{8}-1\times 12=7$$

Least common multiple of 2 and 8 is 8. Convert \frac{5}{2} and \frac{3}{8} to fractions with denominator 8.

$$\frac{20}{8}-\frac{3}{8}-1\times 12=7$$

Since \frac{20}{8} and \frac{3}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-3}{8}-1\times 12=7$$

Subtract 3 from 20 to get 17.

$$\frac{17}{8}-1\times 12=7$$

Multiply 1 and 12 to get 12.

$$\frac{17}{8}-12=7$$

Convert 12 to fraction \frac{96}{8}.

$$\frac{17}{8}-\frac{96}{8}=7$$

Since \frac{17}{8} and \frac{96}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-96}{8}=7$$

Subtract 96 from 17 to get -79.

$$-\frac{79}{8}=7$$

Convert 7 to fraction \frac{56}{8}.

$$-\frac{79}{8}=\frac{56}{8}$$

Compare -\frac{79}{8} and \frac{56}{8}.

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