Solve 5/51*(12+27/52)23^2=

$$\frac{ 5 }{ 51 } \times (12+ \frac{ 27 }{ 52 } ) { 23 }^{ 2 } =$$

Evaluate

$$\frac{573965}{884}\approx 649.281674208$$

Solution Steps

Convert 12 to fraction \frac{624}{52}.

$$\frac{5}{51}\left(\frac{624}{52}+\frac{27}{52}\right)\times 23^{2}$$

Since \frac{624}{52} and \frac{27}{52} have the same denominator, add them by adding their numerators.

$$\frac{5}{51}\times \frac{624+27}{52}\times 23^{2}$$

Add 624 and 27 to get 651.

$$\frac{5}{51}\times \frac{651}{52}\times 23^{2}$$

Multiply \frac{5}{51} times \frac{651}{52} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 651}{51\times 52}\times 23^{2}$$

Do the multiplications in the fraction \frac{5\times 651}{51\times 52}.

$$\frac{3255}{2652}\times 23^{2}$$

Reduce the fraction \frac{3255}{2652} to lowest terms by extracting and canceling out 3.

$$\frac{1085}{884}\times 23^{2}$$

Calculate 23 to the power of 2 and get 529.

$$\frac{1085}{884}\times 529$$

Express \frac{1085}{884}\times 529 as a single fraction.

$$\frac{1085\times 529}{884}$$

Multiply 1085 and 529 to get 573965.

$$\frac{573965}{884}$$

Factor

$$\frac{5 \cdot 7 \cdot 23 ^ {2} \cdot 31}{2 ^ {2} \cdot 13 \cdot 17} = 649\frac{249}{884} = 649.2816742081448$$