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\frac{5}{3}-6x+\frac{7}{2}x=1
Add \frac{7}{2}x to both sides.
\frac{5}{3}-\frac{5}{2}x=1
Combine -6x and \frac{7}{2}x to get -\frac{5}{2}x.
-\frac{5}{2}x=1-\frac{5}{3}
Subtract \frac{5}{3} from both sides.
-\frac{5}{2}x=\frac{3}{3}-\frac{5}{3}
Convert 1 to fraction \frac{3}{3}.
-\frac{5}{2}x=\frac{3-5}{3}
Since \frac{3}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.
-\frac{5}{2}x=-\frac{2}{3}
Subtract 5 from 3 to get -2.
x=-\frac{2}{3}\left(-\frac{2}{5}\right)
Multiply both sides by -\frac{2}{5}, the reciprocal of -\frac{5}{2}.
x=\frac{-2\left(-2\right)}{3\times 5}
Multiply -\frac{2}{3} times -\frac{2}{5} by multiplying numerator times numerator and denominator times denominator.
x=\frac{4}{15}
Do the multiplications in the fraction \frac{-2\left(-2\right)}{3\times 5}.