Solve 5/3-(2/5*7/2-1/3)

$$\frac{ 5 }{ 3 } -( \frac{ 2 }{ 5 } \times \frac{ 7 }{ 2 } - \frac{ 1 }{ 3 } )$$

Evaluate

$$\frac{3}{5}=0.6$$

Solution Steps

Multiply \frac{2}{5} times \frac{7}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5}{3}-\left(\frac{2\times 7}{5\times 2}-\frac{1}{3}\right)$$

Cancel out 2 in both numerator and denominator.

$$\frac{5}{3}-\left(\frac{7}{5}-\frac{1}{3}\right)$$

Least common multiple of 5 and 3 is 15. Convert \frac{7}{5} and \frac{1}{3} to fractions with denominator 15.

$$\frac{5}{3}-\left(\frac{21}{15}-\frac{5}{15}\right)$$

Since \frac{21}{15} and \frac{5}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5}{3}-\frac{21-5}{15}$$

Subtract 5 from 21 to get 16.

$$\frac{5}{3}-\frac{16}{15}$$

Least common multiple of 3 and 15 is 15. Convert \frac{5}{3} and \frac{16}{15} to fractions with denominator 15.

$$\frac{25}{15}-\frac{16}{15}$$

Since \frac{25}{15} and \frac{16}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-16}{15}$$

Subtract 16 from 25 to get 9.

$$\frac{9}{15}$$

Reduce the fraction \frac{9}{15} to lowest terms by extracting and canceling out 3.

$$\frac{3}{5}$$

Factor

$$\frac{3}{5} = 0.6$$