Solve 5/2(-8x-9)=9

$$\frac{ 5 }{ 2 } (-8x-9)=9$$

Solve for x

$$x = -\frac{63}{40} = -1\frac{23}{40} = -1.575$$

Steps for Solving Linear Equation

Multiply both sides by \frac{2}{5}, the reciprocal of \frac{5}{2}.

$$-8x-9=9\times \frac{2}{5}$$

Express 9\times \frac{2}{5} as a single fraction.

$$-8x-9=\frac{9\times 2}{5}$$

Multiply 9 and 2 to get 18.

$$-8x-9=\frac{18}{5}$$

Add 9 to both sides.

$$-8x=\frac{18}{5}+9$$

Convert 9 to fraction \frac{45}{5}.

$$-8x=\frac{18}{5}+\frac{45}{5}$$

Since \frac{18}{5} and \frac{45}{5} have the same denominator, add them by adding their numerators.

$$-8x=\frac{18+45}{5}$$

Add 18 and 45 to get 63.

$$-8x=\frac{63}{5}$$

Divide both sides by -8.

$$x=\frac{\frac{63}{5}}{-8}$$

Express \frac{\frac{63}{5}}{-8} as a single fraction.

$$x=\frac{63}{5\left(-8\right)}$$

Multiply 5 and -8 to get -40.

$$x=\frac{63}{-40}$$

Fraction \frac{63}{-40} can be rewritten as -\frac{63}{40} by extracting the negative sign.

$$x=-\frac{63}{40}$$