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\frac{5}{12}x-\frac{13}{9}+\frac{7}{2}x=-\frac{7}{10}
Add \frac{7}{2}x to both sides.
\frac{47}{12}x-\frac{13}{9}=-\frac{7}{10}
Combine \frac{5}{12}x and \frac{7}{2}x to get \frac{47}{12}x.
\frac{47}{12}x=-\frac{7}{10}+\frac{13}{9}
Add \frac{13}{9} to both sides.
\frac{47}{12}x=-\frac{63}{90}+\frac{130}{90}
Least common multiple of 10 and 9 is 90. Convert -\frac{7}{10} and \frac{13}{9} to fractions with denominator 90.
\frac{47}{12}x=\frac{-63+130}{90}
Since -\frac{63}{90} and \frac{130}{90} have the same denominator, add them by adding their numerators.
\frac{47}{12}x=\frac{67}{90}
Add -63 and 130 to get 67.
x=\frac{67}{90}\times \frac{12}{47}
Multiply both sides by \frac{12}{47}, the reciprocal of \frac{47}{12}.
x=\frac{67\times 12}{90\times 47}
Multiply \frac{67}{90} times \frac{12}{47} by multiplying numerator times numerator and denominator times denominator.
x=\frac{804}{4230}
Do the multiplications in the fraction \frac{67\times 12}{90\times 47}.
x=\frac{134}{705}
Reduce the fraction \frac{804}{4230} to lowest terms by extracting and canceling out 6.