Solve 5/12+4/3div1-(5/12)(4/3)

$$\frac{ 5 }{ 12 } + \frac{ 4 }{ 3 } \div 1-( \frac{ 5 }{ 12 } )( \frac{ 4 }{ 3 } )$$

Evaluate

$$\frac{43}{36}\approx 1.194444444$$

Solution Steps

Anything divided by one gives itself.

$$\frac{5}{12}+\frac{4}{3}-\frac{5}{12}\times \frac{4}{3}$$

Least common multiple of 12 and 3 is 12. Convert \frac{5}{12} and \frac{4}{3} to fractions with denominator 12.

$$\frac{5}{12}+\frac{16}{12}-\frac{5}{12}\times \frac{4}{3}$$

Since \frac{5}{12} and \frac{16}{12} have the same denominator, add them by adding their numerators.

$$\frac{5+16}{12}-\frac{5}{12}\times \frac{4}{3}$$

Add 5 and 16 to get 21.

$$\frac{21}{12}-\frac{5}{12}\times \frac{4}{3}$$

Reduce the fraction \frac{21}{12} to lowest terms by extracting and canceling out 3.

$$\frac{7}{4}-\frac{5}{12}\times \frac{4}{3}$$

Multiply \frac{5}{12} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7}{4}-\frac{5\times 4}{12\times 3}$$

Do the multiplications in the fraction \frac{5\times 4}{12\times 3}.

$$\frac{7}{4}-\frac{20}{36}$$

Reduce the fraction \frac{20}{36} to lowest terms by extracting and canceling out 4.

$$\frac{7}{4}-\frac{5}{9}$$

Least common multiple of 4 and 9 is 36. Convert \frac{7}{4} and \frac{5}{9} to fractions with denominator 36.

$$\frac{63}{36}-\frac{20}{36}$$

Since \frac{63}{36} and \frac{20}{36} have the same denominator, subtract them by subtracting their numerators.

$$\frac{63-20}{36}$$

Subtract 20 from 63 to get 43.

$$\frac{43}{36}$$

Factor

$$\frac{43}{2 ^ {2} \cdot 3 ^ {2}} = 1\frac{7}{36} = 1.1944444444444444$$