Solve 5/-3+3-2-1*5-12--1+4--3*2-4

$$\frac{ 5 }{ -3 } +3-2-1 \cdot 5-12--1+4--3 \cdot 2-4$$

Evaluate

$$-\frac{32}{3}\approx -10.666666667$$

Solution Steps

Fraction \frac{5}{-3} can be rewritten as -\frac{5}{3} by extracting the negative sign.

$$-\frac{5}{3}+3-2-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Convert 3 to fraction \frac{9}{3}.

$$-\frac{5}{3}+\frac{9}{3}-2-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Since -\frac{5}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.

$$\frac{-5+9}{3}-2-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Add -5 and 9 to get 4.

$$\frac{4}{3}-2-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{4}{3}-\frac{6}{3}-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Since \frac{4}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-6}{3}-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Subtract 6 from 4 to get -2.

$$-\frac{2}{3}-1\times 5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Multiply 1 and 5 to get 5.

$$-\frac{2}{3}-5-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Convert 5 to fraction \frac{15}{3}.

$$-\frac{2}{3}-\frac{15}{3}-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Since -\frac{2}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-2-15}{3}-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Subtract 15 from -2 to get -17.

$$-\frac{17}{3}-12-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Convert 12 to fraction \frac{36}{3}.

$$-\frac{17}{3}-\frac{36}{3}-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Since -\frac{17}{3} and \frac{36}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-17-36}{3}-\left(-1\right)+4-\left(-3\times 2\right)-4$$

Subtract 36 from -17 to get -53.

$$-\frac{53}{3}-\left(-1\right)+4-\left(-3\times 2\right)-4$$

The opposite of -1 is 1.

$$-\frac{53}{3}+1+4-\left(-3\times 2\right)-4$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{53}{3}+\frac{3}{3}+4-\left(-3\times 2\right)-4$$

Since -\frac{53}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{-53+3}{3}+4-\left(-3\times 2\right)-4$$

Add -53 and 3 to get -50.

$$-\frac{50}{3}+4-\left(-3\times 2\right)-4$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{50}{3}+\frac{12}{3}-\left(-3\times 2\right)-4$$

Since -\frac{50}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{-50+12}{3}-\left(-3\times 2\right)-4$$

Add -50 and 12 to get -38.

$$-\frac{38}{3}-\left(-3\times 2\right)-4$$

Multiply -3 and 2 to get -6.

$$-\frac{38}{3}-\left(-6\right)-4$$

The opposite of -6 is 6.

$$-\frac{38}{3}+6-4$$

Convert 6 to fraction \frac{18}{3}.

$$-\frac{38}{3}+\frac{18}{3}-4$$

Since -\frac{38}{3} and \frac{18}{3} have the same denominator, add them by adding their numerators.

$$\frac{-38+18}{3}-4$$

Add -38 and 18 to get -20.

$$-\frac{20}{3}-4$$

Convert 4 to fraction \frac{12}{3}.

$$-\frac{20}{3}-\frac{12}{3}$$

Since -\frac{20}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-20-12}{3}$$

Subtract 12 from -20 to get -32.

$$-\frac{32}{3}$$

Factor

$$-\frac{32}{3} = -10\frac{2}{3} = -10.666666666666666$$