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5x-5>0 5x-5<0
Denominator 5x-5 cannot be zero since division by zero is not defined. There are two cases.
5x>5
Consider the case when 5x-5 is positive. Move -5 to the right hand side.
x>1
Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.
4x-7<\frac{3}{5}\left(5x-5\right)
The initial inequality does not change the direction when multiplied by 5x-5 for 5x-5>0.
4x-7<3x-3
Multiply out the right hand side.
4x-3x<7-3
Move the terms containing x to the left hand side and all other terms to the right hand side.
x<4
Combine like terms.
x\in \left(1,4\right)
Consider condition x>1 specified above.
5x<5
Now consider the case when 5x-5 is negative. Move -5 to the right hand side.
x<1
Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.
4x-7>\frac{3}{5}\left(5x-5\right)
The initial inequality changes the direction when multiplied by 5x-5 for 5x-5<0.
4x-7>3x-3
Multiply out the right hand side.
4x-3x>7-3
Move the terms containing x to the left hand side and all other terms to the right hand side.
x>4
Combine like terms.
x\in \emptyset
Consider condition x<1 specified above.
x\in \left(1,4\right)
The final solution is the union of the obtained solutions.