Solve 4x-1/3-8x-2/6

$$\frac{ 4x-1 }{ 3 } - \frac{ 8x-2 }{ 6 }$$

Evaluate

$$0$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 3 and 6 is 6. Multiply \frac{4x-1}{3} times \frac{2}{2}.

$$\frac{2\left(4x-1\right)}{6}-\frac{8x-2}{6}$$

Since \frac{2\left(4x-1\right)}{6} and \frac{8x-2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2\left(4x-1\right)-\left(8x-2\right)}{6}$$

Do the multiplications in 2\left(4x-1\right)-\left(8x-2\right).

$$\frac{8x-2-8x+2}{6}$$

Combine like terms in 8x-2-8x+2.

$$\frac{0}{6}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

$$0$$

Solution Steps

Factor out \frac{1}{3}.

$$\frac{4x-1-\left(4x-1\right)}{3}$$

Simplify.

$$0$$