Solve 4a+6/5geq3a

$$\frac{ 4a+6 }{ 5 } \geq 3a$$

Solve for a

$$a\leq \frac{6}{11}$$

Solution Steps

Multiply both sides of the equation by 5. Since 5 is positive, the inequality direction remains the same.

$$4a+6\geq 15a$$

Subtract 15a from both sides.

$$4a+6-15a\geq 0$$

Combine 4a and -15a to get -11a.

$$-11a+6\geq 0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$-11a\geq -6$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$a\leq \frac{-6}{-11}$$

Fraction \frac{-6}{-11} can be simplified to \frac{6}{11} by removing the negative sign from both the numerator and the denominator.

$$a\leq \frac{6}{11}$$