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\frac{441x^{2}-2500}{225}
Factor out \frac{1}{225}.
\left(21x-50\right)\left(21x+50\right)
Consider 441x^{2}-2500. Rewrite 441x^{2}-2500 as \left(21x\right)^{2}-50^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(21x-50\right)\left(21x+50\right)}{225}
Rewrite the complete factored expression.