Solve 4+1/4+2left(left|4-1right|right)

$$\frac{ 4+1 }{ 4+2 } \left( \left| 4-1 \right| \right)$$

Evaluate

$$\frac{5}{2}=2.5$$

Solution Steps

Add 4 and 1 to get 5.

$$\frac{5}{4+2}|4-1|$$

Add 4 and 2 to get 6.

$$\frac{5}{6}|4-1|$$

Subtract 1 from 4 to get 3.

$$\frac{5}{6}|3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$\frac{5}{6}\times 3$$

Express \frac{5}{6}\times 3 as a single fraction.

$$\frac{5\times 3}{6}$$

Multiply 5 and 3 to get 15.

$$\frac{15}{6}$$

Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.

$$\frac{5}{2}$$

Factor

$$\frac{5}{2} = 2\frac{1}{2} = 2.5$$