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\frac{\left(4+\sqrt{5}\right)\left(2-\sqrt{5}\right)}{\left(2+\sqrt{5}\right)\left(2-\sqrt{5}\right)}
Rationalize the denominator of \frac{4+\sqrt{5}}{2+\sqrt{5}} by multiplying numerator and denominator by 2-\sqrt{5}.
\frac{\left(4+\sqrt{5}\right)\left(2-\sqrt{5}\right)}{2^{2}-\left(\sqrt{5}\right)^{2}}
Consider \left(2+\sqrt{5}\right)\left(2-\sqrt{5}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(4+\sqrt{5}\right)\left(2-\sqrt{5}\right)}{4-5}
Square 2. Square \sqrt{5}.
\frac{\left(4+\sqrt{5}\right)\left(2-\sqrt{5}\right)}{-1}
Subtract 5 from 4 to get -1.
-\left(4+\sqrt{5}\right)\left(2-\sqrt{5}\right)
Anything divided by -1 gives its opposite.
-\left(8-4\sqrt{5}+2\sqrt{5}-\left(\sqrt{5}\right)^{2}\right)
Apply the distributive property by multiplying each term of 4+\sqrt{5} by each term of 2-\sqrt{5}.
-\left(8-2\sqrt{5}-\left(\sqrt{5}\right)^{2}\right)
Combine -4\sqrt{5} and 2\sqrt{5} to get -2\sqrt{5}.
-\left(8-2\sqrt{5}-5\right)
The square of \sqrt{5} is 5.
-\left(3-2\sqrt{5}\right)
Subtract 5 from 8 to get 3.
-3-\left(-2\sqrt{5}\right)
To find the opposite of 3-2\sqrt{5}, find the opposite of each term.
-3+2\sqrt{5}
The opposite of -2\sqrt{5} is 2\sqrt{5}.