Solve 4*42+2*42.3+7*43+44*2+3*45/18

$$\frac{ 4 \times 42+2 \times 42.3+7 \times 43+44 \times 2+3 \times 45 }{ 18 }$$

Evaluate

$$\frac{3883}{90}\approx 43.144444444$$

Solution Steps

Multiply 4 and 42 to get 168. Multiply 7 and 43 to get 301. Multiply 44 and 2 to get 88. Multiply 3 and 45 to get 135.

$$\frac{168+2\times 42.3+301+88+135}{18}$$

Multiply 2 and 42.3 to get 84.6.

$$\frac{168+84.6+301+88+135}{18}$$

Add 168 and 84.6 to get 252.6.

$$\frac{252.6+301+88+135}{18}$$

Add 252.6 and 301 to get 553.6.

$$\frac{553.6+88+135}{18}$$

Add 553.6 and 88 to get 641.6.

$$\frac{641.6+135}{18}$$

Add 641.6 and 135 to get 776.6.

$$\frac{776.6}{18}$$

Expand \frac{776.6}{18} by multiplying both numerator and the denominator by 10.

$$\frac{7766}{180}$$

Reduce the fraction \frac{7766}{180} to lowest terms by extracting and canceling out 2.

$$\frac{3883}{90}$$

Factor

$$\frac{11 \cdot 353}{2 \cdot 5 \cdot 3 ^ {2}} = 43\frac{13}{90} = 43.144444444444446$$