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6\times 4=\left(x+5\right)\left(x-5\right)
Variable x cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by 6\left(x+5\right), the least common multiple of x+5,6.
24=\left(x+5\right)\left(x-5\right)
Multiply 6 and 4 to get 24.
24=x^{2}-25
Consider \left(x+5\right)\left(x-5\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 5.
x^{2}-25=24
Swap sides so that all variable terms are on the left hand side.
x^{2}=24+25
Add 25 to both sides.
x^{2}=49
Add 24 and 25 to get 49.
x=7 x=-7
Take the square root of both sides of the equation.
6\times 4=\left(x+5\right)\left(x-5\right)
Variable x cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by 6\left(x+5\right), the least common multiple of x+5,6.
24=\left(x+5\right)\left(x-5\right)
Multiply 6 and 4 to get 24.
24=x^{2}-25
Consider \left(x+5\right)\left(x-5\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 5.
x^{2}-25=24
Swap sides so that all variable terms are on the left hand side.
x^{2}-25-24=0
Subtract 24 from both sides.
x^{2}-49=0
Subtract 24 from -25 to get -49.
x=\frac{0±\sqrt{0^{2}-4\left(-49\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -49 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-49\right)}}{2}
Square 0.
x=\frac{0±\sqrt{196}}{2}
Multiply -4 times -49.
x=\frac{0±14}{2}
Take the square root of 196.
x=7
Now solve the equation x=\frac{0±14}{2} when ± is plus. Divide 14 by 2.
x=-7
Now solve the equation x=\frac{0±14}{2} when ± is minus. Divide -14 by 2.
x=7 x=-7
The equation is now solved.