Solve for x
x=-20
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4=3x\left(10+3x\right)^{-1}\times \frac{20}{6}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
4=3x\left(10+3x\right)^{-1}\times \frac{10}{3}
Reduce the fraction \frac{20}{6} to lowest terms by extracting and canceling out 2.
4=10x\left(10+3x\right)^{-1}
Multiply 3 and \frac{10}{3} to get 10.
10x\left(10+3x\right)^{-1}=4
Swap sides so that all variable terms are on the left hand side.
10\times \frac{1}{3x+10}x=4
Reorder the terms.
10\times 1x=4\left(3x+10\right)
Variable x cannot be equal to -\frac{10}{3} since division by zero is not defined. Multiply both sides of the equation by 3x+10.
10x=4\left(3x+10\right)
Multiply 10 and 1 to get 10.
10x=12x+40
Use the distributive property to multiply 4 by 3x+10.
10x-12x=40
Subtract 12x from both sides.
-2x=40
Combine 10x and -12x to get -2x.
x=\frac{40}{-2}
Divide both sides by -2.
x=-20
Divide 40 by -2 to get -20.
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