Solve 4/7-2-1-1/4left(2-1/3right)

$$\frac{ 4 }{ 7 } -2-1- \frac{ 1 }{ 4 } \left( 2- \frac{ 1 }{ 3 } \right)$$

Evaluate

$$-\frac{239}{84}\approx -2.845238095$$

Solution Steps

Convert 2 to fraction \frac{14}{7}.

$$\frac{4}{7}-\frac{14}{7}-1-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Since \frac{4}{7} and \frac{14}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4-14}{7}-1-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Subtract 14 from 4 to get -10.

$$-\frac{10}{7}-1-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Convert 1 to fraction \frac{7}{7}.

$$-\frac{10}{7}-\frac{7}{7}-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Since -\frac{10}{7} and \frac{7}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-10-7}{7}-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Subtract 7 from -10 to get -17.

$$-\frac{17}{7}-\frac{1}{4}\left(2-\frac{1}{3}\right)$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{17}{7}-\frac{1}{4}\left(\frac{6}{3}-\frac{1}{3}\right)$$

Since \frac{6}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{17}{7}-\frac{1}{4}\times \frac{6-1}{3}$$

Subtract 1 from 6 to get 5.

$$-\frac{17}{7}-\frac{1}{4}\times \frac{5}{3}$$

Multiply \frac{1}{4} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{17}{7}-\frac{1\times 5}{4\times 3}$$

Do the multiplications in the fraction \frac{1\times 5}{4\times 3}.

$$-\frac{17}{7}-\frac{5}{12}$$

Least common multiple of 7 and 12 is 84. Convert -\frac{17}{7} and \frac{5}{12} to fractions with denominator 84.

$$-\frac{204}{84}-\frac{35}{84}$$

Since -\frac{204}{84} and \frac{35}{84} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-204-35}{84}$$

Subtract 35 from -204 to get -239.

$$-\frac{239}{84}$$

Factor

$$-\frac{239}{84} = -2\frac{71}{84} = -2.8452380952380953$$