Solve 4/6+2+1/6-2=5(6)-6/6^2-4

$$\frac{ 4 }{ 6+2 } + \frac{ 1 }{ 6-2 } = \frac{ 5(6)-6 }{ { 6 }^{ 2 } -4 }$$

Verify

Solution Steps

Add 6 and 2 to get 8.

$$\frac{4}{8}+\frac{1}{6-2}=\frac{5\times 6-6}{6^{2}-4}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{1}{2}+\frac{1}{6-2}=\frac{5\times 6-6}{6^{2}-4}$$

Subtract 2 from 6 to get 4.

$$\frac{1}{2}+\frac{1}{4}=\frac{5\times 6-6}{6^{2}-4}$$

Least common multiple of 2 and 4 is 4. Convert \frac{1}{2} and \frac{1}{4} to fractions with denominator 4.

$$\frac{2}{4}+\frac{1}{4}=\frac{5\times 6-6}{6^{2}-4}$$

Since \frac{2}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{4}=\frac{5\times 6-6}{6^{2}-4}$$

Add 2 and 1 to get 3.

$$\frac{3}{4}=\frac{5\times 6-6}{6^{2}-4}$$

Multiply 5 and 6 to get 30.

$$\frac{3}{4}=\frac{30-6}{6^{2}-4}$$

Subtract 6 from 30 to get 24.

$$\frac{3}{4}=\frac{24}{6^{2}-4}$$

Calculate 6 to the power of 2 and get 36.

$$\frac{3}{4}=\frac{24}{36-4}$$

Subtract 4 from 36 to get 32.

$$\frac{3}{4}=\frac{24}{32}$$

Reduce the fraction \frac{24}{32} to lowest terms by extracting and canceling out 8.

$$\frac{3}{4}=\frac{3}{4}$$

Compare \frac{3}{4} and \frac{3}{4}.

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