Solve for x
x=\frac{45z}{4}-10y
Solve for y
y=\frac{9z}{8}-\frac{x}{10}
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\frac{4}{5}x-9z=-8y
Subtract 8y from both sides. Anything subtracted from zero gives its negation.
\frac{4}{5}x=-8y+9z
Add 9z to both sides.
\frac{4}{5}x=9z-8y
The equation is in standard form.
\frac{\frac{4}{5}x}{\frac{4}{5}}=\frac{9z-8y}{\frac{4}{5}}
Divide both sides of the equation by \frac{4}{5}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{9z-8y}{\frac{4}{5}}
Dividing by \frac{4}{5} undoes the multiplication by \frac{4}{5}.
x=\frac{45z}{4}-10y
Divide -8y+9z by \frac{4}{5} by multiplying -8y+9z by the reciprocal of \frac{4}{5}.
8y-9z=-\frac{4}{5}x
Subtract \frac{4}{5}x from both sides. Anything subtracted from zero gives its negation.
8y=-\frac{4}{5}x+9z
Add 9z to both sides.
8y=-\frac{4x}{5}+9z
The equation is in standard form.
\frac{8y}{8}=\frac{-\frac{4x}{5}+9z}{8}
Divide both sides by 8.
y=\frac{-\frac{4x}{5}+9z}{8}
Dividing by 8 undoes the multiplication by 8.
y=\frac{9z}{8}-\frac{x}{10}
Divide -\frac{4x}{5}+9z by 8.
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